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semester review part 1 1) list three other names for x. list three othe…

Question

semester review part 1

  1. list three other names for x. list three other names for y

(some text is unclear here)

  1. what is the equation of the line ( x - 7y = 14 ) in slope - intercept form?
  2. which of the following numbers is not a solution to the inequality ( -7leq4n + 1lt5 )?

a) -2 b) -1 c) 0 d) 1
(there is some red - inked work here)

  1. the perimeter of the triangle below is 53 feet. find the value of x.

(the triangle has sides ( 4x ), ( 4(2x - 1) ), ( 3(3x - 2) ))

  1. if the following relation is a function, which ordered pair could be the missing point?

( {(-7,17),(-2,7),(5,-7),(x,y)} )
a) ( (5,-12) ) b) ( (-7,15) ) c) ( (0,3) ) d) ( (-2,16) )

  1. write the equation of the line that passes through the points ( (-8,-4) ) and ( (4,-7) ).
  2. use the following non - standard operation ( aotimes b = 5a^{4}+4b ) to evaluate ( -3otimes1 ).

Explanation:

Question 2:

Step1: Recall slope - intercept form

The slope - intercept form of a line is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. We need to solve the equation \(x-7y = 14\) for \(y\).

Step2: Isolate the \(y\) term

Subtract \(x\) from both sides of the equation: \(- 7y=-x + 14\).

Step3: Solve for \(y\)

Divide each term in the equation \(-7y=-x + 14\) by \(-7\). So \(y=\frac{-x}{-7}+\frac{14}{-7}\), which simplifies to \(y=\frac{1}{7}x-2\).

Step1: Solve the inequality \(-7\leq4n + 1\lt5\)

First, solve the left - hand side of the compound inequality \(-7\leq4n + 1\). Subtract 1 from both sides: \(-7-1\leq4n\), so \(-8\leq4n\). Divide both sides by 4: \(-2\leq n\).

Then, solve the right - hand side \(4n + 1\lt5\). Subtract 1 from both sides: \(4n\lt5 - 1=4\). Divide both sides by 4: \(n\lt1\).

The solution to the compound inequality is \(-2\leq n\lt1\).

Step2: Check each option

  • Option A: \(n=-2\). Since \(-2\) is equal to the lower bound of the solution set \(-2\leq n\lt1\), \(-2\) is a solution.
  • Option B: \(n = - 1\). Since \(-2\leq-1\lt1\), \(-1\) is a solution.
  • Option C: \(n = 0\). Since \(-2\leq0\lt1\), \(0\) is a solution.
  • Option D: \(n = 1\). But our solution set is \(n\lt1\), so \(1\) is not a solution.

Step1: Recall the formula for the perimeter of a triangle

The perimeter \(P\) of a triangle is the sum of the lengths of its three sides. Given the sides \(4x\), \(4(2x - 1)\) and \(3(3x - 2)\) and \(P = 53\) feet. So we can write the equation: \(4x+4(2x - 1)+3(3x - 2)=53\).

Step2: Expand the expressions

Expand \(4(2x - 1)=8x-4\) and \(3(3x - 2)=9x - 6\). The equation becomes \(4x + 8x-4+9x - 6=53\).

Step3: Combine like terms

Combine the \(x\) terms: \(4x+8x + 9x=21x\). Combine the constant terms: \(-4-6=-10\). So the equation is \(21x-10 = 53\).

Step4: Solve for \(x\)

Add 10 to both sides: \(21x=53 + 10=63\). Divide both sides by 21: \(x = 3\).

Answer:

\(y=\frac{1}{7}x - 2\)

Question 3: