Question

2
select the correct answer.
which polynomial is equivalent to this expression?
\\(\frac{(x + 2)(x - 1)}{x - 1}\\)
\\(\bigcirc\\) a. \\(x - 1\\)
\\(\bigcirc\\) b. \\((x + 2)(x - 1)\\)
\\(\bigcirc\\) c. \\(x + 1\\)
\\(\bigcirc\\) d. \\(x + 2\\)

Explanation:

Step1: Identify the domain restriction

First, we note that the original expression \(\frac{(x + 2)(x - 1)}{x - 1}\) has a domain restriction: \(x
eq1\) because we cannot divide by zero.

Step2: Simplify the expression

For \(x
eq1\), we can cancel out the common factor \((x - 1)\) in the numerator and the denominator. So, \(\frac{(x + 2)\cancel{(x - 1)}}{\cancel{x - 1}}=x + 2\) (with the understanding that \(x
eq1\)).

Answer:

D. \(x + 2\)