select the correct answer.
given: $ \overline { a b } \parallel \overline { d c } $, and $ \angle b $ and $ \angle d $ are right angles
prove: $ \angle p q b \cong \angle r s d $

which step is missing in the proof?
$ \bigcirc $ a. statement: $ \triangle b q p \sim \triangle s r d $ reason: reflexive property of similarity
$ \bigcirc $ b. statement: $ \triangle b q p \sim \triangle s r d $ reason: hl
$ \bigcirc $ c. statement: $ \triangle b p q \sim \triangle d r s $ reason: ssa
$ \bigcirc $ d. statement: $ \triangle b p q \sim \triangle d r s $ reason: transitive property of similarity

Question

select the correct answer.
given: $ \overline { a b } \parallel \overline { d c } $, and $ \angle b $ and $ \angle d $ are right angles
prove: $ \angle p q b \cong \angle r s d $

which step is missing in the proof?
$ \bigcirc $ a. statement: $ \triangle b q p \sim \triangle s r d $ reason: reflexive property of similarity
$ \bigcirc $ b. statement: $ \triangle b q p \sim \triangle s r d $ reason: hl
$ \bigcirc $ c. statement: $ \triangle b p q \sim \triangle d r s $ reason: ssa
$ \bigcirc $ d. statement: $ \triangle b p q \sim \triangle d r s $ reason: transitive property of similarity

Accepted Answer

# Explanation:
## Step1: Analyze the given similar triangles
We know that $\triangle BAC\sim\triangle BPQ$ (by AA) and $\triangle DCA\sim\triangle DRS$ (by AA), and $\triangle BAC\sim\triangle DCA$ (by AA).
## Step2: Use the transitive property of similarity
If $A\sim B$ and $B\sim C$, then $A\sim C$. Here, since $\triangle BAC\sim\triangle BPQ$ and $\triangle BAC\sim\triangle DCA$ and $\triangle DCA\sim\triangle DRS$, we can say $\triangle BPQ\sim\triangle DRS$ by the transitive property of similarity.

# Answer:
D. Statement: $\triangle BPQ\sim\triangle DRS$ Reason: transitive property of similarity

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Analyze the given similar triangles

Step2: Use the transitive property of similarity

Answer: