QUESTION IMAGE
Question
select the correct answer from each drop - down menu.
given: \\( \angle xob \cong \angle aox \\)
prove: \\( m\angle xob=90^{\circ} \\)
| statements | reasons |
|---|---|
| 2. \\( \angle xob \\) and \\( \angle aox \\) are supplementary | 2. linear pair theorem |
| 3. \\( m\angle xob+m\angle aox = 180^{\circ} \\) | 3. definition of supplementary angles |
| 4. \\( m\angle xob=m\angle aox \\) | 4. definition of congruence |
| 5. \\( 2m\angle xob = 180^{\circ} \\) | 5. substitution property of equality |
| 6. \\( m\angle xob = 90^{\circ} \\) | 6. division property of equality |
write the proof in a paragraph format.
since \\( \overline{aob} \\) forms a line segment, \\( \angle xob \\) and \\( \angle aox \\) are supplementary by the. using the definition of supplementary angles, \\( m\angle xob+m\angle aox = 180^{\circ} \\). since it is given that \\( \angle xob \cong \angle aox \\), then \\( m\angle xob=m\angle aox \\). applying the, then \\( 2m\angle xob = 180^{\circ} \\). after dividing, \\( m\angle xob = 90^{\circ} \\).
Since \(\overline{AOB}\) forms a line segment, \(\angle XOB\) and \(\angle AOX\) are supplementary. The linear - pair theorem states that if two angles form a linear pair (they are adjacent and their non - common sides form a straight line), then they are supplementary. So the first blank is filled with "linear pair theorem".
We know that \(m\angle XOB + m\angle AOX=180^{\circ}\) and \(m\angle XOB = m\angle AOX\) (because \(\angle XOB\cong\angle AOX\)). Substituting \(m\angle AOX\) with \(m\angle XOB\) in the equation \(m\angle XOB + m\angle AOX = 180^{\circ}\) (using the substitution property of equality: if \(a = b\), then \(a\) can be substituted for \(b\) in an equation). So the second blank is filled with "substitution property of equality".
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First blank: linear pair theorem; Second blank: substitution property of equality.