QUESTION IMAGE
Question
select the correct answer from each drop - down menu. in the given image, line ab is parallel to line dc and $overline{df}congoverline{bf}$. complete the table.
| statements | reasons |
|---|---|
| $angle fdccongangle fba$ | |
| $angle afbcongangle$ | |
| $overline{df}congoverline{bf}$ | |
| $\triangle dfccong\triangle bfa$ |
options for reasons: alternate interior angles theorem, same - side interior angles, vertical angles theorem, corresponding angles theorem
Step1: Identify angle - angle relationship for ∠FDC and ∠FBA
Since line AB || line DC, by the alternate - interior angles theorem, when a transversal (the line passing through F) intersects two parallel lines AB and DC, ∠FDC and ∠FBA are alternate - interior angles. So the reason for ∠FDC≅∠FBA is the alternate interior angles theorem.
Step2: Identify the vertical - angle pair
∠AFB and ∠DFC are vertical angles. By the vertical angles theorem, vertical angles are congruent. So the angle that ∠AFB is congruent to is ∠DFC and the reason is the vertical angles theorem.
Step3: Prove triangle congruence
We have ∠FDC≅∠FBA (alternate interior angles), ∠AFB≅∠DFC (vertical angles), and DF≅BF (given). By the Angle - Angle - Side (AAS) congruence criterion, △DFC≅△BFA.
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| Statements | Reasons |
|---|---|
| ∠FDC≅∠FBA | alternate interior angles theorem |
| ∠AFB≅∠DFC | vertical angles theorem |
| DF≅BF | given |
| △DFC≅△BFA | AAS congruence criterion |