Question

select the correct answer from the drop - down menu.
the design for a two - tank system is shown. the inner tank must be surrounded by oxygen with a density of 0.0827 pounds per cubic foot.
what amount of oxygen is needed in the outer tank?
to meet the density required, approximately pounds of oxygen is required.

Explanation:

Step1: Calculate the volume of the outer tank

The volume of a rectangular prism is \(V = l\times w\times h\). For the outer tank, \(l = 20\) ft, \(w = 8\) ft, \(h = 6\) ft. So \(V_{outer}=20\times8\times6=960\) cubic feet.

Step2: Calculate the volume of the inner tank

For the inner tank, \(l = 5\) ft, \(w = 4\) ft, \(h = 3\) ft. So \(V_{inner}=5\times4\times3 = 60\) cubic feet.

Step3: Calculate the volume of oxygen

The volume of oxygen \(V = V_{outer}-V_{inner}\). So \(V=960 - 60=900\) cubic feet.

Step4: Calculate the mass of oxygen

We know that density \(
ho=0.0827\) pounds per cubic foot and mass \(m=
ho\times V\). So \(m = 0.0827\times900=74.43\) pounds.

Answer:

\(74.43\)