Question

1. select all the equations that have the same solution as $2x - 5 = 15$.

a. $2x = 10$
b. $2x = 20$
c. $2(x - 5) = 15$
d. $2x - 20 = 0$
e. $4x - 10 = 30$
f. $15 = 5 - 2x$

1. the number of hours spent in an airplane on a single flight is recorded on a dot plot.

the mean is 5 hours and the standard deviation is approximately 5.82 hours. the
median is 4 hours and the iqr is 3 hours. the value 26 hours is an outlier that should
be deleted in the data

Explanation:

Step1: Solve the equation \(2x - 5=15\)

Add \(5\) to both sides of the equation:
\(2x-5 + 5=15 + 5\)
\(2x=20\)
Divide both sides by \(2\):
\(x = 10\)

Step2: Solve equation A (\(2x = 10\))

Divide both sides by \(2\):
\(x=\frac{10}{2}=5\)

Step3: Solve equation B (\(2x = 20\))

Divide both sides by \(2\):
\(x=\frac{20}{2}=10\)

Step4: Solve equation C (\(2(x - 5)=15\))

First, distribute the \(2\):
\(2x-10 = 15\)
Add \(10\) to both sides:
\(2x-10 + 10=15 + 10\)
\(2x=25\)
Divide both sides by \(2\):
\(x=\frac{25}{2}=12.5\)

Step5: Solve equation D (\(2x-20 = 0\))

Add \(20\) to both sides:
\(2x-20 + 20=0 + 20\)
\(2x=20\)
Divide both sides by \(2\):
\(x = 10\)

Step6: Solve equation E (\(4x-10 = 30\))

Add \(10\) to both sides:
\(4x-10+10 = 30 + 10\)
\(4x=40\)
Divide both sides by \(4\):
\(x = 10\)

Step7: Solve equation F (\(15=5 - 2x\))

Subtract \(5\) from both sides:
\(15-5=5 - 2x-5\)
\(10=-2x\)
Divide both sides by \(-2\):
\(x=-5\)

Answer:

B. \(2x = 20\), D. \(2x-20 = 0\), E. \(4x - 10=30\)