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Question
section 2: special right triangles (10 problems - calculators ok)
- 45-45-90 triangle: hypotenuse = 20. legs = ______ each
- 45-45-90 triangle: each leg = 11. hypotenuse = ______
- 30-60-90 triangle: shorter leg = 7. longer leg = ____ hypotenuse = ____
- 30-60-90 triangle: longer leg = 10√3. shorter leg = ____ hypotenuse = ____
- 30-60-90 triangle: hypotenuse = 24. shorter leg = ____ longer leg = ____
- a 20-meter ladder leans against a wall at 45°. how far up the wall does it reach?
- tree casts 18 m shadow, sun makes 30° angle of elevation with ground. tree height = ______
- equilateral triangle has side length 16. find the exact area.
Problem 9:
Step1: Recall 45-45-90 triangle ratios
In a 45-45-90 triangle, the legs are equal, and the hypotenuse \( h \) is related to the leg \( l \) by \( h = l\sqrt{2} \), so \( l=\frac{h}{\sqrt{2}} \).
Step2: Substitute hypotenuse value
Given \( h = 20 \), then \( l=\frac{20}{\sqrt{2}}=\frac{20\sqrt{2}}{2}=10\sqrt{2} \).
Step1: Recall 45-45-90 triangle ratios
For a 45-45-90 triangle, hypotenuse \( h = l\sqrt{2} \), where \( l \) is the leg length.
Step2: Substitute leg value
Given \( l = 11 \), so \( h = 11\sqrt{2} \).
Step1: Recall 30-60-90 triangle ratios
In a 30-60-90 triangle, shorter leg \( s \), longer leg \( l = s\sqrt{3} \), hypotenuse \( h = 2s \).
Step2: Find longer leg
Given \( s = 7 \), longer leg \( l = 7\sqrt{3} \).
Step3: Find hypotenuse
Hypotenuse \( h = 2\times7 = 14 \).
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\( 10\sqrt{2} \)