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simplify the following expression. if the answer contains exponents, all exponents shou
\\(\frac{(s^8)^2 (s^2)^3}{(s^2)^6}\\) =
question help: basic funcs trig

Explanation:

Step1: Apply power of a power rule

For each term, multiply exponents:
$(s^8)^2 = s^{8 \times 2} = s^{16}$
$(s^2)^3 = s^{2 \times 3} = s^6$
$(s^2)^6 = s^{2 \times 6} = s^{12}$
The expression becomes $\frac{s^{16} s^{6}}{s^{12}}$

Step2: Apply product of powers rule

Add exponents in the numerator:
$s^{16} s^{6} = s^{16+6} = s^{22}$
The expression becomes $\frac{s^{22}}{s^{12}}$

Step3: Apply quotient of powers rule

Subtract exponents:
$s^{22-12} = s^{10}$

Answer:

$s^{10}$