Question

9.6
score: 13/15 answered: 13/15
question 14
the length and width of a rectangle are consecutive odd integers. the perimeter is 80 meters. find the length and width.
the length is meters long while the width is meters.
question help: video message instructor

Explanation:

Step1: Let the width be \(x\)

Since length and width are consecutive odd integers, length \(=x + 2\)
Perimeter of rectangle \(P=2(l + w)\)
Given \(P = 80\), so \(2(x+(x + 2))=80\)

Step2: Simplify the equation

\(2(2x+2)=80\)
\(4x + 4=80\)
\(4x=80 - 4\)
\(4x=76\)
\(x=\frac{76}{4}=19\)

Step3: Find the length

Length \(=x + 2=19+2 = 21\)

Answer:

The length is \(21\) meters long while the width is \(19\) meters.