Question

sample a
mass of each particle: 44 u
average particle speed: 1,500 m/s
compare the average kinetic energies of the particles in each sample. which sample has the higher temperature?
sample a
sample b
neither; the samples have the same temperature
sample b
mass of each particle: 40 u
average particle speed: 1,500 m/s

Explanation:

Step1: Recall kinetic - energy formula

The formula for the kinetic energy of a particle is $K = \frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the speed.

Step2: Calculate kinetic energy for sample A

For sample A, $m_A=44\ u$ and $v = 1500\ m/s$. So $K_A=\frac{1}{2}\times44\times(1500)^{2}= 22\times2250000 = 49500000$ (ignoring the unit of mass - unit conversion for relative comparison).

Step3: Calculate kinetic energy for sample B

For sample B, $m_B = 40\ u$ and $v = 1500\ m/s$. So $K_B=\frac{1}{2}\times40\times(1500)^{2}=20\times2250000 = 45000000$.

Step4: Compare kinetic energies

Since $K_A>K_B$, and temperature is related to the average kinetic energy of particles (higher average kinetic energy means higher temperature for the same type of substance in the same state).

Answer:

sample A