Question

if the same amount of water leaks each hour, how after 60 hours?
water (gallons) \t4 \t
hours \t24 \t60

Explanation:

Step1: Find the leakage rate

The rate of water leakage is constant. From the table, in 24 hours, 4 gallons leak. So the rate $r$ is $\frac{4}{24}=\frac{1}{6}$ gallons per hour.

Step2: Calculate leakage in 60 hours

Using the rate, the amount of water leaked in 60 hours is $r\times60=\frac{1}{6}\times60 = 10$ gallons. Alternatively, set up a proportion: $\frac{4}{24}=\frac{x}{60}$, cross - multiply: $24x = 4\times60$, $24x=240$, then $x=\frac{240}{24}=10$.

Answer:

10