Question

1. sally and ray work together on an assignment. they have broken down the work into 4 parts of the same size. sally works at 2 times the speed of ray but has 5 pieces of work to do for another subject. this problem can be represented by the following system of equations: image of a graph 6b write down the solution to the system of equations as an ordered pair (x, y). (x, y) = 3, 1 (x, y) = 3, 1 (x, y) = (3, 1) 6c how many parts of the assignment did sally do? sallys contribution = enter your next step here parts

Explanation:

Step1: Analyze the system's solution

From 6b, the solution to the system is \((x, y) = (3, 1)\). Typically, in work - rate problems with two variables (like Sally and Ray's work), \(x\) and \(y\) can represent the number of parts each does. Since Sally works faster (2 times Ray's speed) but has other work, we assume \(x\) is Sally's parts and \(y\) is Ray's parts, or vice - versa. But from the context of the work being broken into 4 parts, and the solution \((3,1)\), we check if \(3 + 1=4\) (which it does, as the total work is 4 parts).

Step2: Determine Sally's contribution

Since Sally works at 2 times Ray's speed, Sally should do more parts. So if the ordered pair is \((Sally's\ parts, Ray's\ parts)=(3,1)\), then Sally's contribution is 3 parts. Also, we can verify: Let Ray's rate be \(r\), Sally's rate is \(2r\). Let time be \(t\) for Ray, and \(t\) (or adjusted, but from the solution, the number of parts Sally does is 3 as \(3+1 = 4\) (total parts) and Sally is faster so she does more.

Answer:

3