Question

rse order of operations. check your solutions. b) $-6 = -3(k - 4)$

Explanation:

Step1: Expand the right-hand side

$-6 = -3k + 12$

Step2: Subtract 12 from both sides

$-6 - 12 = -3k + 12 - 12$
$-18 = -3k$

Step3: Divide by -3 on both sides

$\frac{-18}{-3} = \frac{-3k}{-3}$
$6 = k$

Step4: Verify the solution

Substitute $k=6$ into original equation:
Left-hand side: $-6$
Right-hand side: $-3(6-4) = -3(2) = -6$
Both sides are equal, so the solution is valid.

Answer:

$k=6$