Question

rotate △cde 270° clockwise around the origin.

Explanation:

Step1: Determine the coordinates of points \(C\), \(D\), and \(E\)

Assume \(E=(2,0)\), \(C=(6,0)\), \(D=(6, - 4)\) (based on the grid - like graph structure).
The rule for a \(270^{\circ}\) clockwise rotation about the origin \((x,y)\to(y, - x)\)

Step2: Apply the rotation rule to each point

For point \(E=(2,0)\):
After rotation, \(E'=(0, - 2)\) (using the formula \((x,y)\to(y, - x)\) with \(x = 2\) and \(y = 0\))
For point \(C=(6,0)\):
After rotation, \(C'=(0, - 6)\) (using the formula \((x,y)\to(y, - x)\) with \(x = 6\) and \(y = 0\))
For point \(D=(6,-4)\):
After rotation, \(D'=(-4, - 6)\) (using the formula \((x,y)\to(y, - x)\) with \(x = 6\) and \(y=-4\))

Answer:

The coordinates of the vertices of the rotated triangle \(\triangle C'D'E'\) are \(E'(0, - 2)\), \(C'(0, - 6)\), and \(D'(-4, - 6)\)