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Question
rhombus lmno is shown with its diagonals. the length of \\( \overline { l n } \\) is 28 centimeters. what is the length of \\( \overline { l p } \\)? 7 cm 9 cm 14 cm 21 cm
Step1: Recall the property of rhombus diagonals
In a rhombus, the diagonals bisect each other. That is, if the diagonals of rhombus \(LMNO\) are \(LN\) and \(MO\) intersecting at point \(P\), then \(LP=\frac{1}{2}LN\).
Step2: Substitute the given value of \(LN\)
Given \(LN = 28\) cm. Using the formula \(LP=\frac{1}{2}LN\), we substitute \(LN\) into the formula: \(LP=\frac{1}{2}\times28\).
$$LP = 14$$
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\(14\) cm (the third option)