Question

rewrite using a single positive exponent.

\\8^{-2} \cdot 8^{-6}\\

Explanation:

Apply the product rule of exponents

$$ 8^{-2} \cdot 8^{-6} = 8^{-2 + (-6)} = 8^{-8} $$

Apply the negative exponent rule

$$ 8^{-8} = \frac{1}{8^8} $$

Answer:

Rewrite using a single positive exponent.

\(8^{-2} \cdot 8^{-6} =\) <blank>\(\frac{1}{8^8}\)</blank>