QUESTION IMAGE
Question
- reflect the figure shown over the y-axis. record the coordinates of the image.
grid with points m, a, t, h
m ____ a __ t __ h ____
Step1: Recall reflection over y - axis rule
The rule for reflecting a point \((x,y)\) over the \(y\) - axis is \((x,y)\to(-x,y)\).
Step2: Find coordinates of original points
- For point \(M\): From the graph, the coordinates of \(M\) are \((-8,2)\).
- For point \(A\): The coordinates of \(A\) are \((-7,6)\).
- For point \(T\): The coordinates of \(T\) are \((-2,6)\).
- For point \(H\): The coordinates of \(H\) are \((-2,2)\).
Step3: Apply reflection rule to each point
- For \(M(-8,2)\): Using the rule \((x,y)\to(-x,y)\), we get \(M'=(8,2)\) (since \(-(-8)=8\) and \(y = 2\) remains the same).
- For \(A(-7,6)\): Applying the rule, we have \(A'=(7,6)\) (because \(-(-7)=7\) and \(y = 6\) remains unchanged).
- For \(T(-2,6)\): Using the reflection rule, \(T'=(2,6)\) (as \(-(-2)=2\) and \(y = 6\) stays the same).
- For \(H(-2,2)\): Applying the rule, \(H'=(2,2)\) (since \(-(-2)=2\) and \(y = 2\) remains as it is).
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\(M'(8,2)\), \(A'(7,6)\), \(T'(2,6)\), \(H'(2,2)\)