Question

refer to the accompanying data display that results from a sample of airport data speeds in mbps. complete parts (a) through (c) below. tinterval (13 046,22 15) x=17 598 sx=16 01712719 n=50 a. express the confidence interval in the format that uses the less than symbol. given that the original listed data use one decimal place, round the confidence interval limits accordingly 13 05 mbps < μ < 22 15 mbps (round to two decimal places as needed.) b. identify the best point estimate of μ and the margin of error. the point estimate of μ is 17 60 mbps (round to two decimal places as needed.) the margin of error is e = □ mbps (round to two decimal places as needed.)

Explanation:

Step1: Recall the formula for margin of error

The formula for margin of error \(E\) in a confidence interval \(\bar{x}-E <\mu<\bar{x} + E\) is \(E=\bar{x}-(\text{lower limit})\) (or \(E = (\text{upper limit})-\bar{x}\)).

Step2: Substitute the values

We know \(\bar{x}=17.598\approx17.60\) (rounded to two decimal places), lower limit \(L = 13.046\approx13.05\). Then \(E=\bar{x}-L\).
Substitute \(\bar{x}=17.60\) and \(L = 13.05\) into the formula: \(E=17.60 - 13.05\).

Step3: Calculate the value

\(E=17.60-13.05 = 4.55\)

Answer:

\(4.55\)