Question

a rectangle has a length of x + 3 and a width of 2x - 1. what is its area? 2x^2 + 3x - 1 2x^2 + 5x - 3 3x + 2 6x + 4

Explanation:

Step1: Recall area formula

The area $A$ of a rectangle is $A = \text{length}\times\text{width}$.

Step2: Substitute given values

Here, length $l=x + 3$ and width $w=2x-1$, so $A=(x + 3)(2x-1)$.

Step3: Expand the product

Using FOIL method:
First terms: $x\times2x=2x^{2}$.
Outer terms: $x\times(-1)=-x$.
Inner terms: $3\times2x = 6x$.
Last terms: $3\times(-1)=-3$.
Combining like - terms: $A=2x^{2}-x + 6x-3=2x^{2}+5x - 3$.

Answer:

B. $2x^{2}+5x - 3$