Question

the rectangle cdef, shown below, is reflected across the x - axis to form the image cdef.
draw
write the coordinates of the vertices of cdef.
show your work here

Explanation:

Step1: Recall the reflection rule

When a point \((x,y)\) is reflected across the \(x -\)axis, the rule is \((x,y)\to(x, - y)\).

Step2: Find coordinates of \(C\)

The coordinates of \(C\) are \((- 10,-3)\). Using the reflection rule \((x,y)\to(x, - y)\), for point \(C(-10,-3)\), we get \(C'(-10,3)\) since \(-(-3)=3\).

Step3: Find coordinates of \(D\)

The coordinates of \(D\) are \((-6,-3)\). Using the reflection rule \((x,y)\to(x, - y)\), for point \(D(-6,-3)\), we get \(D'(-6,3)\) since \(-(-3)=3\).

Step4: Find coordinates of \(E\)

The coordinates of \(E\) are \((-6,-9)\). Using the reflection rule \((x,y)\to(x, - y)\), for point \(E(-6,-9)\), we get \(E'(-6,9)\) since \(-(-9)=9\).

Step5: Find coordinates of \(F\)

The coordinates of \(F\) are \((-10,-9)\). Using the reflection rule \((x,y)\to(x, - y)\), for point \(F(-10,-9)\), we get \(F'(-10,9)\) since \(-(-9)=9\).

Answer:

\(C'(-10,3)\), \(D'(-6,3)\), \(E'(-6,9)\), \(F'(-10,9)\)