Question

a recipe for a rice dish calls for 15 oz of a rice mixture that is 20% wild rice and 9 oz of pure wild rice. what is the percent concentration of wild rice in the 24 - ounce mixture?

Explanation:

Step1: Calculate amount of wild - rice in the first mixture

The first rice mixture is 15 oz and 20% of it is wild - rice. So the amount of wild - rice in the 15 - oz mixture is $15\times0.2 = 3$ oz.

Step2: Calculate total amount of wild - rice

The first mixture has 3 oz of wild - rice and the second is 9 oz of pure wild - rice. So the total amount of wild - rice is $3 + 9=12$ oz.

Step3: Calculate the percent concentration

The total mixture is 24 oz. The percent concentration of wild - rice is $\frac{12}{24}\times100\% = 50\%$.

Answer:

50%