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5. rearrange the expression from the previous question to solve for p₂ …

Question

  1. rearrange the expression from the previous question to solve for p₂ i need a hint p₂ = \frac{(a)(b)}{c} choices: v₁ v₂ p₁

Explanation:

Assuming the original formula is Boyle's Law: \( P_1V_1 = P_2V_2 \) (since pressure - volume relationships are common in physics, a subfield of Natural Science).

Step1: Start with Boyle's Law

We have the equation \( P_1V_1=P_2V_2 \).

Step2: Solve for \( P_2 \)

To isolate \( P_2 \), we divide both sides of the equation by \( V_2 \). So, \( P_2 = \frac{P_1V_1}{V_2} \). Looking at the choices (assuming A, B, C correspond to \( P_1 \), \( V_1 \), \( V_2 \) in numerator and denominator as per the fraction structure), the numerator should be \( P_1V_1 \) and the denominator \( V_2 \). If we assume the fraction is \( \frac{\text{(A) (B)}}{\text{(C)}} \), then A is \( P_1 \), B is \( V_1 \), C is \( V_2 \) to get \( P_2=\frac{P_1V_1}{V_2} \).

Answer:

Assuming the fraction structure \( P_2=\frac{\text{(A) (B)}}{\text{(C)}} \), A: \( P_1 \), B: \( V_1 \), C: \( V_2 \) (so filling A with \( P_1 \), B with \( V_1 \), C with \( V_2 \) to get \( P_2 = \frac{P_1V_1}{V_2} \))