Question

read the story.
devonports daffodil festival holds an egg hunt every year. the organizers hide plastic eggs filled with small toys and candy throughout the town center. theres a 5% chance that an egg also has a golden ticket inside that can be redeemed for a larger prize. cody finds 12 eggs during the egg hunt. how likely is it that at least 1 of his eggs has a golden ticket inside?
cody simulates the situation by using a computer to randomly generate 12 numbers from 1 to 20. each time 1 appears, it represents a golden ticket.
this table shows the results of 200 trials:
based on codys results, what is the probability that at least 1 of his eggs has a golden ticket inside?

Explanation:

Step1: Find the number of trials with at least 1 golden ticket

The number of trials with at least 1 golden ticket is the total number of trials minus the number of trials with 0 golden tickets.
Total number of trials \(n = 200\), number of trials with 0 golden tickets \(m=108\).
So the number of trials with at least 1 golden ticket \(=200 - 108=92\)

Step2: Calculate the probability

The probability \(P=\frac{\text{Number of trials with at least 1 golden ticket}}{\text{Total number of trials}}\times100\%\)
\(P=\frac{92}{200}\times 100\% = 46\%\)

Answer:

\(46\%\)