Question

read each question and choose the best answer. then write the letter for the answer you have chosen in the blank at the right of each question. objective the student, given a problem situation, will collect, analyze, display, and interpret data, using histograms. 1 which is a reasonable conclusion based on this histogram showing the ages of audience members at a comedy club? a the club can seat only 100 people. b there were fewer teens than people aged 60 and older. c the club attracts mainly people aged 60 and older. d more men than women visit the club. for questions 2 and 3, use this histogram which shows the minutes students spent during one week practicing the piano. 2 which is a true statement? f most of the students practiced more than 40 minutes. g most of the students practiced 120 minutes. h more students practiced between 41 and 60 minutes than students who practiced between 61 and 80 minutes. j fewer students practiced less than 60 minutes than students who practiced more than 100 minutes. 3 how many students are represented on this histogram? a 8 b 19 c 28 d 34

Explanation:

Question 1

• Option A: The histogram shows frequency of ages, not seating capacity. Eliminate A.
• Option B: The "0 - 20" (teens) bar is shorter than "61 - 80" and "81 - 100" combined? Wait, "0 - 20" frequency is low, "61 - 80" is moderate, "81 - 100" is low. Wait, "teens" (0 - 20) has low frequency, "60 and older" includes "61 - 80" (moderate) and "81 - 100" (low). Wait, "21 - 40" and "41 - 60" are higher. Wait, re - evaluate: "0 - 20" (teens) has a small bar, "61 - 80" has a bar similar to "21 - 40"? Wait no, the first histogram: 0 - 20 is low, 21 - 40 is moderate, 41 - 60 is high, 61 - 80 is moderate, 81 - 100 is low. So "teens" (0 - 20) have fewer than "60 and older" (61 - 80 + 81 - 100). So B is correct? Wait, no: "60 and older" is 61 - 80 and 81 - 100. The 61 - 80 bar is about 30, 81 - 100 is low (maybe 5). 0 - 20 is about 5. Wait, maybe I miscalculated. Wait, the 0 - 20 bar is very short, 61 - 80 is a moderate bar, 81 - 100 is very short. So "teens" (0 - 20) have fewer than "60 and older" (61 - 80 + 81 - 100)? Wait, 61 - 80 is, say, 30, 81 - 100 is 5, total 35. 0 - 20 is 5. So yes, fewer teens than 60 and older.
• Option C: The highest bar is "41 - 60", so the club attracts mainly 41 - 60, not 60 and older. Eliminate C.
• Option D: Histogram shows ages, not gender. Eliminate D. So B is correct.

• Option F: "More than 40 minutes" includes "41 - 60", "61 - 80", "81 - 100", "101 - 120". The frequencies for these: 41 - 60 (6), 61 - 80 (8), 81 - 100 (5), 101 - 120 (4). Sum: 6 + 8+5 + 4 = 23. "0 - 40" includes "0 - 20" (2), "21 - 40" (3). Sum: 2 + 3 = 5. So most students practiced more than 40 minutes. Let's check other options.
• Option G: "120 minutes" is in "101 - 120", which has frequency 4, not most. Eliminate G.
• Option H: "41 - 60" has frequency 6, "61 - 80" has 8. 6 < 8, so "more students" in 41 - 60 than 61 - 80 is false. Eliminate H.
• Option J: "Less than 60 minutes" includes "0 - 20" (2), "21 - 40" (3), "41 - 60" (6). Sum: 2+3 + 6 = 11. "More than 100 minutes" is "101 - 120" (4). 11 > 4, so "fewer" is false. Eliminate J. So F is correct.

Step 1: Sum the frequencies of each interval.

The intervals and their frequencies:

• 0 - 20: 2
• 21 - 40: 3
• 41 - 60: 6
• 61 - 80: 8
• 81 - 100: 5
• 101 - 120: 4

Step 2: Calculate the total.

Total = 2+3 + 6+8 + 5+4
= (2 + 3)+6 + 8+5 + 4
= 5+6 + 8+5 + 4
= 11+8 + 5+4
= 19+5 + 4
= 24+4
= 28? Wait, wait, maybe I misread the frequencies. Let's re - check the histogram:

• 0 - 20: 2
• 21 - 40: 3
• 41 - 60: 6
• 61 - 80: 8
• 81 - 100: 5
• 101 - 120: 4

Sum: 2+3 = 5; 5+6 = 11; 11+8 = 19; 19+5 = 24; 24+4 = 28? But option C is 28, option B is 19. Wait, maybe I misread the frequencies. Wait the "Piano Practice" histogram:

• 0 - 20: 2
• 21 - 40: 3
• 41 - 60: 6
• 61 - 80: 8
• 81 - 100: 5
• 101 - 120: 4

Wait 2+3 = 5, 5+6 = 11, 11+8 = 19, 19+5 = 24, 24+4 = 28. So the total is 28. So option C.

Answer:

B

Question 2