Question

#2 $sqrt{24}$ c) rational d) irrational

Explanation:

Step1: Simplify the square - root

We know that $\sqrt{24}=\sqrt{4\times6}$. Using the property $\sqrt{ab}=\sqrt{a}\times\sqrt{b}$ ($a = 4$, $b = 6$), we get $\sqrt{24}=\sqrt{4}\times\sqrt{6}=2\sqrt{6}$.

Step2: Determine if it's rational or irrational

A rational number can be written as a fraction $\frac{p}{q}$ where $p$ and $q$ are integers and $q
eq0$. Since $\sqrt{6}$ is an irrational number (it cannot be written as a fraction of two integers) and $2\sqrt{6}$ is a non - zero multiple of an irrational number, $2\sqrt{6}$ (i.e., $\sqrt{24}$) is irrational.

Answer:

D. Irrational