Question

h = \frac{ka\delta t}{l}
the rate of heat transfer, h, of a material can be expressed in terms of its thermal conductivity, ka, the change in temperature of the material, \delta t, and the thickness of the material, l, as shown in the given equation. which of the following correctly expresses the thermal conductivity of a material in terms of its thickness, its change in temperature, and its rate of heat transfer?
choose 1 answer:
a ka = \frac{\delta t}{hl}
b ka = \frac{hl}{\delta t}
c ka = hl\delta t
d ka = \frac{h\delta t}{l}

Explanation:

Step1: Cross - multiply the given equation

Given $H=\frac{kA\Delta T}{L}$, cross - multiplying gives $HL = kA\Delta T$.

Step2: Solve for $kA$

Dividing both sides of $HL = kA\Delta T$ by $\Delta T$ (assuming $\Delta T
eq0$), we get $kA=\frac{HL}{\Delta T}$.

Answer:

B. $kA=\frac{HL}{\Delta T}$