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question 6/7 wz = 41.5 m m∠5 = 106° m∠6 = 37° m∠xwz =

Question

question 6/7
wz = 41.5 m
m∠5 = 106°
m∠6 = 37°
m∠xwz =

Explanation:

Step1: Use the property of the exterior angle of a triangle

The exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. In triangle \(WZQ\), \(\angle5\) is an exterior angle, and \(\angle6\) and \(\angle XWZ\) are non - adjacent interior angles. So, \(m\angle5=m\angle6 + m\angle XWZ\).

Step2: Solve for \(m\angle XWZ\)

Rearrange the formula from Step1: \(m\angle XWZ=m\angle5 - m\angle6\).
Substitute \(m\angle5 = 106^{\circ}\) and \(m\angle6=37^{\circ}\) into the formula: \(m\angle XWZ=106 - 37\).

Answer:

\(69\)