Question

question
what is the volume of a cylinder, in cubic feet, with a height of 11 feet and a base diameter of 18 feet? round to the nearest tenths place.
answer attempt 1 out of 2
v = ft³ submit answer

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume \( V \) of a cylinder is \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.

Step2: Find the radius of the base

Given the diameter of the base \( d = 18 \) feet. The radius \( r=\frac{d}{2}=\frac{18}{2} = 9 \) feet.

Step3: Substitute the values of \( r \) and \( h \) into the formula

We know \( r = 9 \) feet and \( h=11 \) feet. Substituting these into the formula \( V=\pi r^{2}h \), we get \( V=\pi\times(9)^{2}\times11 \).
First, calculate \( 9^{2}=81 \). Then, \( V=\pi\times81\times11=891\pi \).

Step4: Calculate the numerical value and round to the nearest tenths place

Using \( \pi\approx3.14159 \), we have \( V = 891\times3.14159\approx2790.7 \) (rounded to the nearest tenths place).

Answer:

\( 2790.7 \)