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what is the sum of 3 of the interior angles of a regular pentagon?
answer attempt 1 out of 2
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Step1: Find interior angle of regular pentagon
The formula for the sum of interior angles of a polygon is \((n - 2)\times180^{\circ}\), where \(n\) is the number of sides. For a pentagon, \(n = 5\). So the sum of interior angles is \((5 - 2)\times180^{\circ}= 540^{\circ}\). Since it's regular, each interior angle is \(\frac{540^{\circ}}{5}=108^{\circ}\).
Step2: Calculate sum of 3 interior angles
Multiply one interior angle by 3: \(3\times108^{\circ}=324^{\circ}\).
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\(324\)