Question

question what is the image point of (-6, -1) after the transformation r_y = x ∘ d_5? answer attempt 1 out of 2 ( ) submit answer

Explanation:

Step1: 先进行伸缩变换

$D_5$表示以原点为中心，缩放比例为5的伸缩变换。对于点$(x,y)$，经过$D_5$变换后变为$(5x,5y)$。对于点$(-6,-1)$，经过$D_5$变换后为$(5\times(-6),5\times(-1))=(-30,-5)$。

Step2: 再进行关于$y = x$的反射变换

关于$y = x$反射变换的规则是$(x,y)\to(y,x)$。那么点$(-30,-5)$经过$r_{y = x}$变换后为$(-5,-30)$。

Answer:

$(-5,-30)$