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Question
question
use the quadratic formula to solve. express your answer in simplest form.
$5n^2 - 30n + 20 = -n$
Step1: Rewrite to standard quadratic form
$5n^2 - 30n + 20 + n = 0$
$5n^2 - 29n + 20 = 0$
Step2: Identify a, b, c values
For $ax^2+bx+c=0$, $a=5$, $b=-29$, $c=20$
Step3: Substitute into quadratic formula
Quadratic formula: $n=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$n=\frac{-(-29)\pm\sqrt{(-29)^2-4(5)(20)}}{2(5)}$
Step4: Calculate discriminant
$\sqrt{841 - 400}=\sqrt{441}=21$
Step5: Simplify to find solutions
$n=\frac{29\pm21}{10}$
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$n=5$ and $n=\frac{4}{5}$