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question 6 of 6
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an architect created a layout for an office building. the roof of the building is at an elevation of 48.2 feet, and the floor of the basement is at an elevation of -10.6 feet.
a company logo is being installed on the outer wall of the building at an elevation equal to \\(\frac{3}{5}\\) the total height of the office building, including the basement.
what is the elevation at which the logo is being installed?
\\(\square\\) feet
Step1: Calculate total height
The total height of the building is the difference between the roof elevation and the basement elevation. So, \( 48.2 - (-10.6) = 48.2 + 10.6 = 58.8 \) feet.
Step2: Find 3/5 of total height
Calculate \( \frac{3}{5} \) of 58.8. \( \frac{3}{5} \times 58.8 = 3 \times 11.76 = 35.28 \)
Step3: Add basement elevation
The elevation of the logo is the basement elevation plus the height from basement to logo. So, \( -10.6 + 35.28 = 24.68 \)
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24.68