Question

question
solve the system of equations ( 4x + 3y = -2 ) and ( 7x + 3y = 19 ) by combining the equations
( (4x + 3y = -2) )( (7x + 3y = 19) )
( 4x + 3y = -2 )( 7x + 3y = 19 )
( overline{-3x + 0y = -21} )
solve for ( x ):
( -3x = -21 )( x = 7 )
plug in ( x = 7 ) into either equation and solve for ( y )
( 4x + 3y = -2 ) or ( 7x + 3y = 19 )
( y = square )
answer attempt 1 out of 2

Explanation:

Step1: Choose an equation to substitute \( x = 7 \)

We have the system of equations:
\( 4x + 3y = -2 \) and \( 7x + 3y = 19 \)
Let's substitute \( x = 7 \) into the first equation \( 4x + 3y = -2 \).

Step2: Substitute \( x = 7 \) into the equation

Substitute \( x = 7 \) into \( 4x + 3y = -2 \):
\( 4(7) + 3y = -2 \)
Calculate \( 4(7) \): \( 4\times7 = 28 \)
So the equation becomes \( 28 + 3y = -2 \)

Step3: Solve for \( y \)

Subtract 28 from both sides:
\( 3y = -2 - 28 \)
\( 3y = -30 \)
Divide both sides by 3:
\( y = \frac{-30}{3} \)
\( y = -10 \)

Answer:

\( y = -10 \)