Question

question 5 1 pts two identical freight cars roll without friction (one at 1 m/s, the other at 2 m/s) toward each other on a level track. they collide, couple together, and roll away in the direction of the slower car the faster car neither, for they stop question 6 1 pts a piece of putty moving with 1 unit of momentum strikes and sticks to a heavy bowling ball that is initially at rest. both move with a combined momentum of more than 1 unit. 1 unit. less than 1 unit. need more information

Explanation:

Step1: Define momentum formula

Momentum $p = mv$. Let the mass of each freight - car be $m$. The momentum of the first car $p_1=mv_1$ and the second car $p_2 = mv_2$. Assume the direction of the faster car as positive, so $v_1=- 1\ m/s$ and $v_2 = 2\ m/s$.

Step2: Calculate total initial momentum

$P_{total}=p_1 + p_2=m\times(-1)+m\times2=m( - 1 + 2)=m\gt0$. Since the total initial momentum is positive, the combined cars will move in the direction of the faster car.

For Question 6:

Step1: Apply conservation of momentum

In a closed - system (no external forces), the total momentum before the collision is equal to the total momentum after the collision. The initial momentum of the putty is $p_{putty}=1$ unit and the initial momentum of the bowling ball $p_{ball}=0$ (at rest).

Step2: Determine final combined momentum

By the law of conservation of momentum $P_{initial}=P_{final}$. So $P_{final}=p_{putty}+p_{ball}=1 + 0=1$ unit.

Answer:

Question 5: the faster car
Question 6: 1 unit