Question

question 5 points 2
rebecca has a bag that contains a blue ball, a black ball, and a red ball. find the probability of getting a black ball and then a red ball without replacing the black ball.
\\(\frac{1}{3}\\)
\\(\frac{1}{6}\\)
\\(\frac{2}{3}\\)
\\(\frac{1}{2}\\)

Explanation:

Step1: Probability of black ball

There are 3 balls (blue, black, red). Probability of black ball: $\frac{1}{3}$.

Step2: Probability of red ball (no replacement)

After removing black, 2 balls left. Probability of red: $\frac{1}{2}$.

Step3: Multiply probabilities

Multiply the two probabilities: $\frac{1}{3} \times \frac{1}{2} = \frac{1}{6}$.

Answer:

$\frac{1}{6}$ (corresponding to the option with $\frac{1}{6}$)