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Question
question 3 (3 points)
find \\( \tan 90 ^ { 0 } \\)
-1
1
0
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Step1: Recall the tangent formula
$\tan\theta=\frac{\sin\theta}{\cos\theta}$
Step2: Substitute $\theta = 90^{\circ}$
When $\theta = 90^{\circ}$, $\sin90^{\circ}=1$ and $\cos90^{\circ}=0$. So $\tan90^{\circ}=\frac{1}{0}$.
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