Question

question 8 (1 point)

the restriction(s) on the expression \\(\frac{x + 2}{x^2 + x - 2}\\) is/are

a) \\(x \
eq -2, x \
eq 1\\)

b) \\(x \
eq -2\\)

c) \\(x \
eq 2\\)

d) \\(x \
eq 2, x \
eq -1\\)

Explanation:

Identify the condition for restrictions

$$ x^2 + x - 2 eq 0 $$

Factor the quadratic denominator

$$ (x + 2)(x - 1) eq 0 $$

Solve for the restricted values

$$
LATEXBLOCK0
$$

Answer:

• **A) \(x

eq -2, x
eq 1\) (Correct answer)**

• B) \(x

eq -2\)

• C) \(x

eq 2\)

• D) \(x

eq 2, x
eq -1\)