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question 5 of 6 (1 point) | question attempt: 1 of unlimited
\\( \left\\{ \
$$\begin{array} { l } { y = - \\frac { 1 } { 2 } x + 3 } \\\\ { - x - 2 y = - 6 } \\end{array}$$
\
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o solution\ or \infinitely many\ solutions.
Step1: Rearrange the second equation
Starting with \(-x - 2y=-6\), we can solve for \(y\). Add \(x\) to both sides: \(-2y=x - 6\). Then divide by \(-2\): \(y=-\frac{1}{2}x + 3\).
Step2: Analyze the system of equations
The first equation is \(y =-\frac{1}{2}x+3\) and the second equation, after rearrangement, is also \(y =-\frac{1}{2}x + 3\). Since the two equations are identical.
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