Question

question 6 (1 point) (01.06 mc) if (overline{us}) is an angle bisector of (angle rut), find (mangle rut).
a (mangle rut = 80^circ)
b (mangle rut = 40^circ)
c (mangle rut = 20^circ)
d (mangle rut = 10^circ)

Explanation:

Step1: Recall Angle Bisector Definition

An angle bisector divides an angle into two equal parts. So, if \(\overrightarrow{US}\) bisects \(\angle RUT\), then \(\angle RUS=\angle SUT\).

Step2: Identify Given Angle

We know \(\angle RUS = 40^\circ\), so \(\angle SUT=y^\circ = 40^\circ\) (since \(US\) is the bisector).

Step3: Calculate \(\angle RUT\)

\(\angle RUT=\angle RUS+\angle SUT\). Substituting the values, we get \(\angle RUT = 40^\circ+ 40^\circ=80^\circ\).

Answer:

a. \(m\angle RUT = 80^\circ\)