Question

question
perform the operation.
$(2x^2 - 3x + 1) + (7x^2 + 10x + 8)$

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. Since there are no negative signs outside the parentheses to distribute, we can simply write the terms as they are: $2x^{2}-3x + 1+7x^{2}+10x + 8$.

Step2: Combine like terms

• For the $x^{2}$ terms: $2x^{2}+7x^{2}=(2 + 7)x^{2}=9x^{2}$.
• For the $x$ terms: $-3x+10x=(-3 + 10)x = 7x$.
• For the constant terms: $1 + 8=9$.

Now, we combine these results: $9x^{2}+7x + 9$.

Answer:

$9x^{2}+7x + 9$