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Question
question 4
multiply the conjugates:
\\(-7 + i)(-7 - i)\\
🆕 New Concept Discovered: Multiplying Complex Conjugates
Multiplying complex numbers to get a real number
Step 1: Identify the pattern
The expression is a product of complex conjugates in the form \( (a + bi)(a - bi) \).
Here, we have:
$$ a = -7 $$
$$ b = 1 $$
When we multiply conjugates, the middle terms cancel out, following the difference of squares pattern:
$$ (a + bi)(a - bi) = a^2 - (bi)^2 = a^2 - b^2 i^2 $$
Since \( i^2 = -1 \), this simplifies to:
$$ a^2 + b^2 $$
Step 2: Substitute the values
Using the formula \( a^2 + b^2 \):
$$ (-7)^2 + (1)^2 $$
Step 3: Simplify the expression
Calculate the squares and add them together:
$$ (-7)^2 = 49 $$
$$ (1)^2 = 1 $$
$$ 49 + 1 = 50 $$
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