Question

question 5 given the function $f(x)=2x^{2}-5x + 5$. calculate the following values: $f(-2)=$ $f(-1)=$ $f(0)=$ $f(1)=$ $f(2)=$ submit question

Explanation:

Step1: Substitute $x = - 2$

$f(-2)=2\times(-2)^2-5\times(-2)+5=2\times4 + 10+5=8 + 10+5=23$

Step2: Substitute $x = - 1$

$f(-1)=2\times(-1)^2-5\times(-1)+5=2\times1+5 + 5=2 + 5+5=12$

Step3: Substitute $x = 0$

$f(0)=2\times0^2-5\times0+5=0-0 + 5=5$

Step4: Substitute $x = 1$

$f(1)=2\times1^2-5\times1+5=2\times1-5 + 5=2$

Step5: Substitute $x = 2$

$f(2)=2\times2^2-5\times2+5=2\times4-10 + 5=8-10 + 5=3$

Answer:

$f(-2)=23$, $f(-1)=12$, $f(0)=5$, $f(1)=2$, $f(2)=3$