Question

question
given: abcd is a parallelogram and b is the midpoint of \\(\overline{af}\\).
prove: \\(\overline{df}\\) bisects \\(\overline{bc}\\).
step\tstatement\treason
1\tabcd is a parallelogram
b is the midpoint of \\(\overline{af}\\)\tgiven
2\t\\(\overline{ab} \cong \overline{bf}\\)\tselect a reason...

Explanation:

Step1: Recall Midpoint Definition

A midpoint of a segment divides it into two congruent segments. Since \( B \) is the midpoint of \( \overline{AF} \), by the definition of a midpoint, \( \overline{AB} \cong \overline{BF} \).

Answer:

The reason for \( \overline{AB} \cong \overline{BF} \) is "Definition of Midpoint" (A midpoint divides a segment into two congruent segments).