Question

question
find the value of x to the nearest tenth.
answer attempt 1 out of 2
x ~

Explanation:

Step1: Find the height of the first right - triangle

Use the Pythagorean theorem \(a^{2}+b^{2}=c^{2}\). Let the height be \(h\), the two sides of the first right - triangle are \(9\) and \(h\), and the hypotenuse is \(10\). So \(h=\sqrt{10^{2}-9^{2}}=\sqrt{100 - 81}=\sqrt{19}\)

Step2: Find the value of \(x\)

In the second right - triangle, using the Pythagorean theorem again. We know one side is \(x\), another side is \(4\), and the hypotenuse is \(h=\sqrt{19}\). Then \(x=\sqrt{(\sqrt{19})^{2}-4^{2}}=\sqrt{19 - 16}=\sqrt{3}\approx1.7\)

Answer:

\(1.7\)