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in the diagram below of triangle abc, d is the midpoint of \\(\overline{ac}\\) and e is the midpoint of \\(\overline{bc}\\). if m\\(\angle cab = -8x + 93\\), and m\\(\angle cde = 99 - 9x\\), what is the measure of \\(\angle cde\\)?
answer attempt 1 out of 2
m\\(\angle cde = \square^\circ\\)
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Step1: Identify the relationship (Midline Theorem)
Since \( D \) is the midpoint of \( AC \) and \( E \) is the midpoint of \( BC \), by the Midline Theorem, \( DE \parallel AB \). Therefore, \( \angle CDE \) and \( \angle CAB \) are supplementary (same - side interior angles). So, \( m\angle CDE + m\angle CAB=180^{\circ} \).
Step2: Set up the equation
We know that \( m\angle CAB = - 8x + 93 \) and \( m\angle CDE=99 - 9x \). Substitute these into the supplementary angle equation:
Step3: Simplify and solve for \( x \)
Combine like terms:
Subtract 192 from both sides:
Divide both sides by - 17:
Wait, this seems wrong. Wait, if \( DE\parallel AB \), then \( \angle CDE \) and \( \angle CAB \) should be equal? Wait, no, let's re - examine the diagram. If \( D \) is the midpoint of \( AC \) and \( E \) is the midpoint of \( BC \), then \( DE\parallel AB \), so \( \angle CDE=\angle CAB \) (corresponding angles). Oh! I made a mistake in the angle relationship.
Let's correct Step1: Since \( DE\parallel AB \), \( \angle CDE \) and \( \angle CAB \) are corresponding angles, so \( m\angle CDE=m\angle CAB \).
Step1 (corrected): Identify the correct relationship
By the Midline Theorem, \( DE\parallel AB \). So, \( \angle CDE\) and \( \angle CAB \) are corresponding angles, so \( m\angle CDE = m\angle CAB \).
Step2 (corrected): Set up the equation
We have \( - 8x + 93=99 - 9x \)
Step3 (corrected): Solve for \( x \)
Add \( 9x \) to both sides:
Subtract 93 from both sides:
Step4: Find \( m\angle CDE \)
Substitute \( x = 6 \) into the expression for \( m\angle CDE \): \( m\angle CDE=99-9x \)
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