Question

question:
consider the function ( y = 2sin(x) ) for ( 0^{circ}leq xleq360^{circ} ).

1. graph the function:

plot the function ( y = 2sin(x) ) on a coordinate plane. label the x - axis as \angle (degrees)\ and the y - axis as \y - value\. mark the coordinates of all key points where the graph intersects the x - axis, reaches its maximum, or minimum within the given interval.

Explanation:

Step1: Find the x - axis intersection points

Set \(y = 0\), then \(2\sin(x)=0\), \(\sin(x)=0\). For \(0^{\circ}\leq x\leq360^{\circ}\), \(x = 0^{\circ},180^{\circ},360^{\circ}\).

Step2: Find the maximum and minimum points

The general form of a sine function is \(y = A\sin(x)+k\). Here \(A = 2,k = 0\). The maximum value of \(\sin(x)\) is \(1\) and the minimum value is \(- 1\).
When \(\sin(x)=1\), \(x = 90^{\circ}\), \(y=2\times1 = 2\).
When \(\sin(x)=-1\), \(x = 270^{\circ}\), \(y=2\times(-1)=-2\).

Answer:

• Intersection points with the x - axis: \((0^{\circ},0),(180^{\circ},0),(360^{\circ},0)\)
• Maximum point: \((90^{\circ},2)\)
• Minimum point: \((270^{\circ},-2)\)