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question choose all answers that describe the polygon vwxy if vw = 12, …

Question

question
choose all answers that describe the polygon vwxy if vw = 12, wx = 12, xy = 12, yv = 12, m∠v = m∠x, and m∠w = m∠y.
answer
parallelogram
quadrilateral
rectangle
rhombus
square
trapezoid

Explanation:

Brief Explanations
  1. Quadrilateral: A polygon with four sides. Since \(VWXY\) has four sides (\(VW, WX, XY, YV\)), it is a quadrilateral.
  2. Parallelogram: A quadrilateral with both pairs of opposite sides equal and both pairs of opposite angles equal. Here, \(VW = XY = 12\) and \(WX = YV = 12\) (opposite sides equal), and \(m\angle V=m\angle X\), \(m\angle W = m\angle Y\) (opposite angles equal), so it is a parallelogram.
  3. Rhombus: A parallelogram with all four sides equal. Since \(VW = WX=XY = YV = 12\), all sides are equal, so it is a rhombus.
  4. Rectangle: A parallelogram with four right angles. We know opposite angles are equal (\(m\angle V=m\angle X\), \(m\angle W = m\angle Y\)) and the sum of interior angles of a quadrilateral is \(360^\circ\). Let \(m\angle V = m\angle X = a\) and \(m\angle W=m\angle Y = b\). Then \(2a + 2b=360^\circ\), or \(a + b = 180^\circ\). If we assume the angles are right angles (since in a rhombus with equal opposite angles summing to \(180^\circ\) per pair, if all sides are equal and opposite angles equal, it can be a rectangle), but actually, since all sides are equal and it's a parallelogram, if angles are right angles, it's a square, but also a rectangle. Wait, more accurately, since it's a parallelogram with all sides equal (rhombus) and if angles are right angles, it's a square (which is also a rectangle). But even without assuming right angles, the given angle conditions (opposite angles equal) and side conditions (all sides equal) make it a parallelogram, rhombus, and since it's a quadrilateral. Also, a square is a special case of rhombus, rectangle, and parallelogram. Let's check square: A square is a rhombus with four right angles. We know all sides are equal, and if we consider the angle sum: \(2a + 2b=360\), and if \(a = b\) (since in a rhombus with all sides equal, if opposite angles are equal and let's see, if \(a=b\), then \(4a = 360\), \(a = 90^\circ\)), so angles are right angles. So:
  • Square: A rhombus with four right angles. Since all sides are equal and angles are right angles (as shown by angle sum: \(2a+2b = 360\), and since it's a rhombus, if we assume symmetry, \(a = b\), so \(a = b=90^\circ\)), so it's a square. A square is also a rectangle (a rectangle with all sides equal) and a parallelogram and a rhombus and a quadrilateral.
  • Trapezoid: A trapezoid has at least one pair of parallel sides. But a parallelogram has two pairs of parallel sides, so it is a trapezoid? Wait, no, in some definitions, a trapezoid has exactly one pair of parallel sides, but in inclusive definitions, it has at least one. However, since it's a parallelogram (two pairs of parallel sides), it would be a trapezoid in inclusive definition, but the main ones here are quadrilateral, parallelogram, rhombus, square, rectangle. Wait, let's re - evaluate:

Wait, the side lengths: \(VW = WX=XY = YV = 12\) (all sides equal), opposite angles equal (\(m\angle V=m\angle X\), \(m\angle W = m\angle Y\)).

  • Quadrilateral: 4 - sided, so yes.
  • Parallelogram: Opposite sides equal (\(VW = XY\), \(WX = YV\)) and opposite angles equal (\(m\angle V=m\angle X\), \(m\angle W = m\angle Y\)), so yes.
  • Rhombus: Parallelogram with all sides equal (\(VW = WX=XY = YV\)), so yes.
  • Square: A rhombus with four right angles. Since the sum of interior angles of a quadrilateral is \(360^\circ\), and \(m\angle V=m\angle X\), \(m\angle W = m\angle Y\), let \(m\angle V=m\angle X = x\) and \(m\angle W=m\angle Y = y\). Then \(2x + 2y=360^\circ\Rightarrow x + y = 180^\circ\). In a rhombus, adjacent angles are supp…

Answer:

Quadrilateral, Parallelogram, Rhombus, Square, Rectangle