Question

question
assuming x and y are both positive, write the following expression in simplest radical form.
3x^{3}y^{3}\sqrt{252x^{7}y^{2}}
answer attempt 1 out of 2
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Explanation:

Step1: Factor the radicand

$252x^7y^2 = 36 \times 7 \times x^6 \times x \times y^2$

Step2: Simplify the square root

$\sqrt{36 \times 7 \times x^6 \times x \times y^2} = 6x^3y\sqrt{7x}$

Step3: Multiply with the outside term

$3x^3y^3 \times 6x^3y\sqrt{7x} = 18x^{3+3}y^{3+1}\sqrt{7x}$

Step4: Combine exponents

$18x^{6}y^{4}\sqrt{7x}$

Answer:

$18x^6y^4\sqrt{7x}$