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question 69
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reduce the following to its lowest terms
\\(\frac{1,000}{125} = a\\)
solve for a in the above question;
question 70
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reduce the following to its lowest terms
\\(\frac{15}{45} = \frac{x}{y}\\)
solve for x in the above question;
solve for y in the above question;

Explanation:

Question 69

Step1: Divide numerator by denominator

To reduce $\frac{1000}{125}$ to lowest terms, we perform the division: $1000 \div 125$.

Step2: Calculate the result

We know that $125 \times 8 = 1000$, so $1000 \div 125 = 8$.

for x (numerator):

Step1: Divide numerator by GCD

To find $x$ (the new numerator), we divide the original numerator (15) by the GCD (15): $15 \div 15$.

Step2: Calculate the result

$15 \div 15 = 1$. So $x = 1$.

for y (denominator):

Step1: Divide denominator by GCD

To find $y$ (the new denominator), we divide the original denominator (45) by the GCD (15): $45 \div 15$.

Step2: Calculate the result

$45 \div 15 = 3$. So $y = 3$.

Answer:

8

Question 70

For reducing $\frac{15}{45}$ to lowest terms, we find the greatest common divisor (GCD) of 15 and 45, which is 15. Then we divide both the numerator and the denominator by 15.